Math, asked by tarunjha1984, 4 months ago

A father was 4 times old as his son 8 years ago. The father is 48 years old now. Find the son's present age.​

Answers

Answered by Tanishk82
2

Hope this helps you

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Answered by kumarrajeev50
1

Answer:

let the son age be =x

father age=4x-8

present age of father=48

present age of son=

4x-8=48

4x=48+8

4x=56

x=56/4

x=14

therefore, present age of son is 14

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