a fathers age is three times the sum of ages of his two children. after 5 years his age will be two times the sum of their ages. find the present age of the father
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Let the sum of ages of children be y
Let the father's age be x
x = 3y 1️⃣
x +5 = 2(y +10) [ since there are 2 children 5 will be added twice to the sum of ages)
x = 2y + 20 - 5
x = 2y + 15 2️⃣
1️⃣ = 2️⃣
3y = 2y + 15
y = 15
x = 15 ×3 = 45
So the present age of the father is 45 years
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