a fathers age is twice his daughters age but 16 years ago the fathers age was 4 times his daughter age .calculate their ages
Answers
Answered by
20
16 years ago=daughter's age=x
her father=4x
2(x+16)=4x+16
2x+32=4x+16
32-16=4x-2x
16=2x
8=x
16+8=24
24×2=48
daughter's age=24
father's age=48
her father=4x
2(x+16)=4x+16
2x+32=4x+16
32-16=4x-2x
16=2x
8=x
16+8=24
24×2=48
daughter's age=24
father's age=48
Similar questions