Question

A faulty liquid-in-glass thermometer shows a reading of 38 degrees celsius when the actual temperature is 35 degrees celsius and a reading of -2degrees celsius at ice point. What reading would the thermometer indicate when it's bulb is dipped in pure boiling water.

Answer 1

Answer:

Relationship between two thermometer is given as,

C

−

0

100

−

0

=

x

−

z

y

−

z

where,

z

is the ice point in the new scale and

y

is the steam point in it.

Given,

z

=

10

∘

C

and

y

=

130

∘

C

so, for

C

=

40

∘

C

,

40

100

=

x

−

10

130

−

10

or,

x

=

58

∘

C

Explanation:

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