Question

a faulty thermometer read 10°c in melting ice and 140°c in boiling point of water at normal atm pressure what will be reading on this thermometer when true thermometer reads 40°c​

Answer 1

Answer:

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Answer 2

Answer:

ANSWER

If a thermometer is wrong calibrated then,

If X the temperature reading on the faulty thermometer scale then,

t=

(UFP−LFP)

(X−LFP)

×100. Where, t=actual reading.

Now, it reads 99

∘

C(UFP) in dry steam and 5

o

C(LFP). So, using formula we can get the actual temperature for 50

∘

C

Using,

5

C

=

9

F−32

reading is actually 50

∘

C=122

∘

F