Question

A feather is dropped on a building from a height of 1.40 meters. Determine the time for
the feather to fall to the surface of the ground.

Answer 1

Explanation:

using, motion under gravity relation

$h = \frac{1}{2} g {t}^{2} \\ 1.40= \frac{1}{2} \times 10 \times {t}^{2} \\ {t}^{2} = 0.28 \\ t = 0.529 \: sec$

hope it'll help