Question

A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s2. Determine the time for the feather to fall to the surface of the moon.​

Answer 1

Given:

vi = 0 m/s

d = -1.40 m

a = -1.67 m/s2

Find:

t = ??

d = vi*t + 0.5*a*t2

-1.40 m = (0 m/s)*(t)+ 0.5*(-1.67 m/s2)*(t)2

-1.40 m = 0+ (-0.835 m/s2)*(t)2

(-1.40 m)/(-0.835 m/s2) = t2

1.68 s2 = t2

t = 1.29 s