Question

A feather is dropped on the Moon from a height of 1.40 meters. Determine the time taken by feather to reach to the surface of the Moon. [Take g = 10 m/s^2] Note: Find the square root by division method. *

Answer 1

Answer:

Explanation:

v^2=u^2+2.a.s   (where v=final velocity , u=initial velocity , s=distance covered , a=acceleration)

so here u=0 ; s=1.4 ; a=1.67

=> v^2 = 0+2*1.67*1.4

           =4.676

 => v = 2.16 m/sec

now,

v=u+at

=>  t = (v-u)/a

       =(2.16-0)/1.67

       =1.294 sec