Physics, asked by priyagosain4505, 9 months ago

A feather is dropped on the moon from a height of 2 m . The acceleration of gravity on the moon is 1.69 m/s sq. Determine the time for the feather to fall to the surface of the moon.

Answers

Answered by gangulisabyasachi270
0

Answer:

Explanation:

Given that, a feather is dropped on the moon from a height of 2 m. The acceleration of gravity on the moon is 1.69 m/s².

We have to find the time taken by the feather to fall to the surface of the moon.

From above data we have; height (s) is 2 m, acceleration due to gravity (a) is 1.69 m/s² and initial velocity (u) is 0 m/s.

First equation of motion:

v = u + at

Second equation of motion:

s = ut + 1/2 at²

Third equation of motion:

v² - u² = 2as

As we have value of of s, u and a. So, using the third equation of motion,

s = ut + 1/2 at²

Substitute the known values in the above formula,

→ 2 = (0)t + 1/2 × 1.69 × t²

→ 2 = 0 + 0.845t²

→ 2 = 0.845t²

→ 2.37 = t²

→ 1.54 = t

Therefore, time taken by the feather to fall to the surface of the moon is 1.54 sec.

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