A feather of mass 20g is dropped from a height. It is found to fall down with a constant velocity. What is the net force acting on it?
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Answer:
The net force acting on it is 19.6\times10^{-2}\ N19.6×10
−2
N
Explanation:
Given that,
Mass = 20 g
When a feather is dropped from a height with a constant velocity it means the acceleration is zero.
So, The net force acting on the feather
F = mg+maF=mg+ma
F = 20\times10^{-3}\times9.8+0F=20×10
−3
×9.8+0
F = 0.196\ NF=0.196 N
F = 196\times10^{-3}\ NF=196×10
−3
N
Hence, The net force acting on it is 19.6\times10^{-2}\ N19.6×10
−2
N
Explanation:
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