A feild is in the form of a rhombus whose each side is 81m and altitude is 25m.find the side of a square field whose area is equal to that of the rhombus. find the difference in their perimeters.
Answers
Answered by
3
area of rhombus =b× a
area=81×25
=2025
area of square= side× side
square a= 2025
area= √2025
area= 45
difference of their perimeter = perimeter of rhombus - parameter of square
81 ×4 - 45 - 4
324-180
144
Answered by
1
Side of rhombus is 81m and its altitude is 25m.
Area of rhombus = side * altitude = 81*25 sqm.
Area of square = 81*25 sqm.
So side of square = sqrt(81*25)= 9*5 = 45m
Perimeter of a rhombus = 4 × 81 = 324m
perimeter of a square = 4 × 45 = 180m
Their difference = 324 - 180 = 144m
Similar questions