Question

A feild is in the shape of a quadrilateral ABCD in which side AB=18m,side AD =24m,side BC=40m,DC=50m and angle A=90 degree.Find the area of the feild

Answer 1

The quadrilateral ABCD is divided into two triangles.  ABD and BCD.

ABD is a right angle triangle.

    Area = 1/2 AB * AD as angle A is 90, AB is the altitude and AD is the base.

            = 1/2 * 18 * 24 = 216 cm^2

    BC^2 = AB^2 + AD^2    =>  BC = 30 cm

BCD triangle  

    s = semi perimeter = 60 cm

area = sqroot(60 * 30 * 20 * 10 ) = 600 cm^2

total area = 816 cm^2