Question

A feild is in the shape of a trapezium whose parallel sides are 25m and 10m non parallel sides are 14m and 13m find the area of the feild​

Answer 1

Step-by-step explanation:

Let ABCD be a trapezium with,

AB∥CD

AB=25m

CD=10m

BC=14m

AD=13m

Draw CE∥DA. So, ADCE is a parallelogram with,

CD=AE=10m

CE=AD=13m

BE=AB−AE=25−10=15m

In ΔBCE, the semi perimeter will be,

s=2a+b+c

s=214+13+15

s=21m

Area of ΔBCE,

A=s(s−a)(s−b)(s−c)

=21(21−14)(21−13)(21−15)

=21(7)(8)(6)

=7056

=84m2

Also, area of ΔBCE is,

A=21×base×height

84=21×15×CL

1584×2=CL

CL=556m

Now, the area of trapezium is,

A=21(sumofparallelsides)(height)

A=21×(25+10)(556)

A=196m2

Therefore, the area of the trapezium is 196m2.

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