Question

a field 150 m long and 120 m wide has two cross roads in its centre. Each road is 3.2m. Find the area of the cross roads.
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Answer 1

Answer:

Step-by-step explanation:

Area of cross road = Area of the rectangle LKGH + area of rectangle  EMFP + area of the rectangle NOIJ

Area of rectangle EMFP= area of rectangle NOIJ (as cross roads runs through the centre of the roads)

Area of cross road = Area of the rectangle LKGH +2 X area of rectangle  EMFP

1. Area of rectangle LKGH= LG X GH

LG=120m

GH= 3.2m

LG X GH = 120 X 3.2 = 384m$^{2}$

2. Area of the rectangle EMFP=EM X EF

EM = (150-3.2) /2 = 73.4

EF =3.2m

EM X EF = 73.4 X 3.2= 234.88 m$^{2}$

Area of Cross road = 384 + 2 X 234.88 = 853.76 m$^{2}$