Question

A field 360 m long and 120 m wide has two cross roads in its centre.Each road is 3 m wide .Find the area of cross roads​

Answer 1

Answer:

43,300 m ^2

Step-by-step explanation:

So, the area of the larger field will be 360m×120m which is equal to 43,200m^2.

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Answer 2

.Diagram.

______________________

| | | | ^

| | | | |

| | | | |

|_________| |_________.| |

|_________ 3 _________..| 120

| | | | |

| | | | |

| | | | |

|_________|_._|_________.| v

<—————-- 360 --————-—>

.Given.

Length of the field = 360 m

Breadth of the field = 120 m

Also ,

Breadth of the road = 3 m

•°• Area of the vertical road =>

= l × b

= 360 × 3

= 1080 m²

Again ,

Area of the horizontal road =>

= l × b

= 120 × 3

= 360 m²

•°• Total area of the roads =>

= ( 1080 + 360 )

= 1440

꧁ 1440 m² ꧂

_____________________

Have a look at these knowledge :

• area of square = s²
• perimeter of square = 4s
• area of rectangle = l × b
• perimeter of rectangle = 2(l+b)
• circumference of circle = 2πr
• area of circle = πr²

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