Question

a field 70 M long and 45 M wide has to cross roads in the centre.each road is 5 M wide find the area of the remaining field.

Answer 1

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Answer 2

The remaining are of the field is 2600 m².

Step-by-step explanation:

Consider the provided information.

A field 70 M long and 45 M wide

Area of rectangle is: $A=Length \times breadth$

Thus, the area of field is: $A=70\times45=3150$

Length of the road parallel to length is 70 M

Breadth of the road parallel to length is 5 M

Area of road parallel to length = 70 × 5 = 350 m²

Now,

The Length of the road parallel to breadth is 5 m

Breadth of the road parallel to breadth is 45 m

Area of the road parallel to breadth = 45 × 5 = 225 m²

The Area of common portion = 5 × 5 = 25 m²

Total area of roads = (350 + 225 – 25) m²

Total area of roads  = 550 m²

The remaining area of field = Total area of field - Total area of road

The remaining area of field = 3150 m² - 550 m²

The remaining area of field = 2600 m²

Hence, the remaining are of the field is 2600 m².

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