a field in a stop
of a Trapezium is parallel side 40 metre 20 m and the 18 distance between18 between them 18 M find the cost of levelling @ rupees 10 per metre square
Answers
Answered by
0
I think so that 5400.......
Answered by
2
hello frnd!!!
here's ur answer
b1=40m b2=20m height=18m
area=1/2×h(b1+b2)
=1/2×18(40+20)
=9×60
=540m^2
total cost of levelling if 1m^2 costs ₹10.
=540×10
=₹5400
hope this help u....
:) :) :)
here's ur answer
b1=40m b2=20m height=18m
area=1/2×h(b1+b2)
=1/2×18(40+20)
=9×60
=540m^2
total cost of levelling if 1m^2 costs ₹10.
=540×10
=₹5400
hope this help u....
:) :) :)
Similar questions