Question

A field in the form of a parallelogram has a base 32 m and altitude 1.75 m . Find the cost of watering the field at ₹ 8 per sq.m

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Answer 1

❏ Using Formula:-

• for a cuboid of dimensions( l×b×h )

1) the diagonal is given by,

$\longrightarrow \sf \boxed{diagonal= \sqrt{l {}^{2} + b {}^{2} + h {}^{2} } }$

2)volume of the Cuboid

$\longrightarrow \sf\boxed{ \: volume =( l \times b \times h)}$

•for a right circular cylinder of base radius r and of height h ,

1)Curved Surface Area(L.S.A),

$\longrightarrow \sf\boxed{ L.S.A.=( 2\pi r h)}$

2)Total Surface Area(T.S.A.),

$\longrightarrow \sf\boxed{ T.S.A.=2\pi r (r+h)}$

3) Volume of,

$\longrightarrow \sf\boxed{ Volume=\pi r{}^{3}h}$

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$\huge\pink{\star}$

•for a parallelogram of base b and altitude h,

3) Area of,

$\longrightarrow \sf\boxed{ Area=b\times h}$

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❏ Question:-

Q) A field in the form of a parallelogram has a base 32 m and altitude 1.75 m . Find the cost of watering the field at ₹ 8 per sq.m.

❏ Solution:-

❚➾ Given:- •base(b)=32 m

• height (h)=1.75 m

$\sf\therefore Area=b\times h$

$\sf\implies Area=(32\times 1.75)\:\:m{}^{2}$

$\sf\implies \boxed{\red{Area=56\:\:m{}^{2}}}$

∴ Total cost of watering the field at 8 Rs/m² is,

$\sf\implies Cost=(56\times8)\:\:Rs$

$\sf\implies \boxed{\red{\large{Cost=448\:\:Rs} }}$

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$\underline{ \huge\mathfrak{hope \: this \: helps \: you}}$

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