a field in the form of a parallelogram has one diagonal of 42 m long and the perpendicular distance of this diagonal from either of the outying verticals is 10 m as shown in the figure find the area of the field
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Here ABCD is a parallelogram has one of its diagonal AC = 42 m.
BE ,DF are perpendicular distance from diagonal to the outlying vertices.
BE = DF = 10
Area of parallelogram ABCD = Area of a ΔABC + Area of a ΔACD.
= ( 1/ 2) x AC X BE + (1 / 2) x AC X DF m2
= (1 / 2) x AC [ BE + DF] m2
= (1 / 2) x 42 x [10 + 10] m2
= 420 m2
Step-by-step explanation:
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