A field in the form of a parallelogram has one of its diagonals 42m long and the
perpendicular distance of this diagonal from either of the outlying vertices is 80 cm. Find
the area of the field.
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0.8m = 80cm
The information can be shown in figure as follows.
a(||gm ABCD) = a(triangle ABD) + a(triangle CBD)
Area of triangle = 1/2 × base × height
Therefore
a(||gm ABCD) = (1/2 × 42 × 0.8) + (1/2 × 42 × 0.8)
= 33.6 m^2
Therefore area of field is 33.6 m^2
The information can be shown in figure as follows.
a(||gm ABCD) = a(triangle ABD) + a(triangle CBD)
Area of triangle = 1/2 × base × height
Therefore
a(||gm ABCD) = (1/2 × 42 × 0.8) + (1/2 × 42 × 0.8)
= 33.6 m^2
Therefore area of field is 33.6 m^2
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