Question

A field in the form of a parallelogram has one of its diagonals 42m long and the perpendicular distance of this diagonal from either of the outlying vertices is 80 cm. Find the area of the field.

Answer 1

the image of the parellalogram is given on the picture above.

diagonal DB=42m
one of the diagonal AE=80cm =0.8m
AE=FC=0.8
this is because,it is a parellalogram in which both the triangles have have equal area.

therefore,
area of field=2×area of the triangle
$= 2 \times \frac{1}{2} \times base \times height$
here the base is the diagonal and the height is the perpendicular distance from either of the side.

$= 2 \times \frac{1}{2} \times 42 \times 0.8$
$= 33.6{m}^{2}$
is the answer.

Answer 2

Answer:

diagonal DB=42m

one of the diagonal AE=80cm =0.8m

AE=FC=0.8

this is because,it is a parellalogram in which both the triangles have have equal area.

therefore,

area of field=2×area of the triangle

here the base is the diagonal and the height is the perpendicular distance from either of the side.

ep-by-step explanation: