A field in the form of a parallelogram has sides 60
m and 40 m and one of its diagonals is 80 m long.
Find the area of the parallelogram.
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Considering parallelogram as two symmetrical triangles with sides 40,60,80 metres
we have
Area of triange= Sqrt(s(s-40)(s-60)(s-80))
s=(40+60+80)/2=90
So area= Sqrt(90*(90-40)*(90-60)*(90-80))
=Sqrt(90*50*30*10)
=300*Sqrt(15)
Since there are two such triangle
Total area of parallelogram =2*300*Sqrt(15)
=600*Sqrt(15) m^2
Therefore the answer is 6)
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