Question

A field in the form of parallelogram has sides 6 cm and 4 cm and one of its diagonals is 8 cm long find the area of the parallelogram

Answer 1

when you draw a parallelogram's diagonal you get 2 equal area triangles

you just have to multiply triangle 1 area with 2

sqrt of(s(s-a)(s-b)(s-c))×2

s is (6+8+4)÷2

=9

answer by solving it

sqrt of(9(9-4)(9-6)(9-8))×2

is equal to 6×sqrt(15)

hope it helps

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