Question

a field in the shape of a quadrilateral has its diagonal as 28 m and the perpendicular distances of other two vertices from the diagonal are 32.5 and 22 m . find the area of the field.

Answer 1

two triangle are formed on base as diagonal
and height given
so area of quad. = 1/2*28*32.5 +1/2*28*22
= 455+308=763

Answer 2

Answer:

The answer is 763 m

Mark me as brainliest.