Question

A field in the shape of a rhombus has the distances between pairs of opposite vertices as 14 m and 48 m.
What is the cost of fencing the field at Rs. 20 per metre:
(A) Rs. 1800
(B) Rs. 1900
(C) Rs. 2000
(D) None of these​

Answer 1

Answer:

C) 2000/-

Step-by-step explanation:

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Length of one side=√{(48÷2)^2+(14×2)^{2} M

➢√{576+49} M

➢√625 M

➢ 25 M

Total perimeter of the field=25×4 M =100 M

Therefore total cost of fencing will be=(100×20)/- =2000