a field in the shape of trapezium and it's area is 396m square 2 if the parallel sides are in the ratio 3:5 find the measure of the sides also find the cost of levelling the field at rate of rs9.50 per m square 2
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Step-by-step explanation:
→ DC = AE = 30 m
SO,
→ EB = AB - AE = 90 - 30 = 60m.
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now, in right angled ACEB,
→ EB = 60m
→ CB = 100 m (given)
then,
→ EC = √(100²-60²) { By pythagoras
theorem }
→ EC = √(10000 - 3600)
→ EC = √6400
→ EC = 80 m
therefore,
→ Area of trapezium = (1/2) * sum of parallel side* height = (1/2) * (30 +90) *
80 (1/2)* 120 * 80 = 60 * 80 = 4800 m².
=
hence,
→ 1 m² cost = Rs.4
→ 4800 m² cost = 4800 * 4 = Rs.19200
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