Question

A field in the shape of trapezium whose parallel sides are 25m and 10m. the non parallel sides are 14m and 13m. find the area of the field.

Answer 1

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Answer 2

Answer:

Draw a line BE parallel to AD and draw a perpendicular BF on CD

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogram

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13m

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10m

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15m

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBEC

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formula

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²=84m²

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²=84m²Area of Δ BEC =½x CE x BF

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²=84m²Area of Δ BEC =½x CE x BF=84=12x15xBF

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²=84m²Area of Δ BEC =½x CE x BF=84=12x15xBFBF=16815=11.2m

Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²=84m²Area of Δ BEC =½x CE x BF=84=12x15xBFBF=16815=11.2mArea of the field = 84+112=196m2