Question

A field is 102 m long and 25 m broad. A tank 10 m long, 5 m broad and 4 m deep is dug out from the middle of the field and the earth removed is evenly spread over the remaining part of the field. Find the rise in the level of the remaining part of the field in centimeters.

Answer 1

Let us take rise in level of the field =h cm

Let us take rise in level of the field =h cmVol. of the earth spread = vol. of the tank

Let us take rise in level of the field =h cmVol. of the earth spread = vol. of the tank Area of the remaining field times rise in level = vol. of the tank

Let us take rise in level of the field =h cmVol. of the earth spread = vol. of the tank Area of the remaining field times rise in level = vol. of the tank(Area of field-area of tank)*rise in level of field= vol. of the tank

Let us take rise in level of the field =h cmVol. of the earth spread = vol. of the tank Area of the remaining field times rise in level = vol. of the tank(Area of field-area of tank)*rise in level of field= vol. of the tank(120∗50−24∗10)∗h=24∗10∗6

Let us take rise in level of the field =h cmVol. of the earth spread = vol. of the tank Area of the remaining field times rise in level = vol. of the tank(Area of field-area of tank)*rise in level of field= vol. of the tank(120∗50−24∗10)∗h=24∗10∗6(6000−240)∗h=1440

Let us take rise in level of the field =h cmVol. of the earth spread = vol. of the tank Area of the remaining field times rise in level = vol. of the tank(Area of field-area of tank)*rise in level of field= vol. of the tank(120∗50−24∗10)∗h=24∗10∗6(6000−240)∗h=1440(5760)∗h=1440

Let us take rise in level of the field =h cmVol. of the earth spread = vol. of the tank Area of the remaining field times rise in level = vol. of the tank(Area of field-area of tank)*rise in level of field= vol. of the tank(120∗50−24∗10)∗h=24∗10∗6(6000−240)∗h=1440(5760)∗h=1440=0.25m=25cm

Let us take rise in level of the field =h cmVol. of the earth spread = vol. of the tank Area of the remaining field times rise in level = vol. of the tank(Area of field-area of tank)*rise in level of field= vol. of the tank(120∗50−24∗10)∗h=24∗10∗6(6000−240)∗h=1440(5760)∗h=1440=0.25m=25cmrise in level of the field= 25cm

hope it helps you

Answer 2

Step-by-step explanation:

Given :

For field,

Length of the field is 102m.

Breadth of the field is 25m.

For tank,

To dug in the middle of the field

Length of the tank is 10m.

Breadth of the tank is 5m.

Deep of the tank is 4m.

Find :

The rise in the level of the remaining part of the field in centimeters.

Solution :

The volume of the tank dug out = 10×5×4 m³

= 200 m³.

The upper surface area of the tank = 10×5 m²

= 50 m².

Total area of the field = 102×25 m²

= 2550 m².

The remaining area of the field = (2550-50) m²

= 2500 m².

Therefore :

The rise in the level remaining part of the field

=> 200/2500 m

=> 2/25 m

=> 2/25 × 100 cm

=> 8 cm.

Hence :

The rise in the level of the remaining part of the field is 8 cm.