Question

A field is 102 m long and 25 m broad . A tank 10 m long 5 mm broad and 4 m deep is dug from the middle of the middle of the field and the earth removed is evenly spread over the remaining part of the field .Find the rise in the level of the remaining part of the field in centimeters

Answer 1

Answer:

8 cm

Step-by-step explanation:

It is given that:

• Length of field is 102 m
• Width of field is 25 m
• Tank dimensions are: 10 m length, 5 m width and 4 m deep.

The volume of the tank = Length*Width*Height

Volume = 10*5*4 = 200 $m^3$.

Area of remaining part of the field = Field length * Field width - (Tank length * Tank width)

Area of remaining part of field = 102*25 - (10*5) = 2500 $m^2$.

Therefore, the rise in the level of the field = $\frac{200}{2500}=0.08\:m=8\:cm$

Answer 2

Step-by-step explanation:

Hope it is helpful to you!!