A field is 120 m long and 50 m broad. A
tank 24 m long, 10 m broad and 6 m deep
is dug any where in the field and the earth
taken out of the tank is evenly spread over
the remaining part of the field. Find the rise
in level of the field.
~THOSE WHO WILL ANSWER I WILL MARK IT AS BRAINLIEST
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3
Answer:
hy dude!
your answer is..
Step-by-step explanation:
It is given that:
Length of field is 102 m
Width of field is 25 m
Tank dimensions are: 10 m length, 5 m width and 4 m deep.
The volume of the tank = Length*Width*Height
Volume = 10*5*4 = 200 m^3m
3
.
Area of remaining part of the field = Field length * Field width - (Tank length * Tank width)
Area of remaining part of field = 102*25 - (10*5) = 2500 m^2m
2
.
Therefore, the rise in the level of the field = \frac{200}{2500}=0.08\:m=8\:cm
2500
200
=0.08m=8cm.
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