Question

a field is 120 metre long 50m. A tank24 metre long and 10 metre broad and 6m deep is is Dug anywhere in the field and the earth taken out of the tank is evenly spread over the remaining part of the will find the rise in the level of the field​

Answer 1

Solution

Given ,

• a field is 120 long 50m broad .
• a tank is 24m long 10 metre broad and 6 metre deep dug anywhere in the field and the earth taken out of the tank is evenly spread over the remaining part of the field .

To find ,

• the rise in the level of the field.

As ,

• the length of the field = 20 m
• the breadth of the field = 50m
• length of the tank = 24 m
• breadth of the tank = 10m
• depth of the tank = 6m

So ,

Let us take rise in Level of the field = H m

• volume of the earth spread = volume of the tank .
• area of the remaining field times rise in level = volume of the tank
• area of field area of tank = the volume of the tank

Then ,

=> (120×50-24×10)×h = 24×10×6

=> ( 6000 - 240) ×h = 1440

=> 5760 × h =1440

=> 5760h = 1440

=>h = 1440÷5760

=> h =0. 25 m = 25cm

So , the rise in level of the field = 0.25 m / 25cm .

Answer 2

Answer:

25 cm

Step-by-step explanation:

Let us take the rise in level of the field = h cm

Vol. of the earth spread = Vol. of the tank

Area of remaining field times rise in level =

Vol. of the tank

(Area of field-area of tank) *rise in level of field=

Vol. of the tank

(120*50-24*10) * h = 24*10*6

(6000-240)*h =1440

(5760) *h=1440

=0.25m=25cm

Rise in level of the field =25cm

* = multiply