Question

A field is 120m long & 50m broad. A tank 24m long, 10m broad & 6m deep is dug anywhere in the field and the earth taken out of the tank is evenly spread over the remaining part of the field. Find the rise in the level of the field.

Answer 1

Answer :

›»› The rise in the level of the field is 0.25 m.

Given :

• A field is 120m long & 50m broad. A tank 24m long, 10m broad & 6m deep is dug anywhere in the field and the earth taken out of the tank is evenly spread over the remaining part of the field.

To Find :

• The rise in the level of the field = ?

Solution :

⠀⋆ Length of a field = 120 m.

⠀⋆ Breadth of a field = 50 m.

⠀⋆ Length of a tank = 24 m.

⠀⋆ Breadth of a tank = 10 m.

⠀⋆ Depth of a tank = 6 m.

Field is in the form of rectangle.

As we know that

→ Area of field = length * breadth

→ Area of field = 120 * 50

→ Area of field = 6000 m².

Tank is also in the form of rectangle.

As we know that

→ Area of tank = length * breadth

→ Area of tank = 24 * 10

→ Area of tank = 240 m².

→ Area of the remaining field = Area of field - Area of tank.

→ Area of the remaining field = 6000 - 240

→ Area of the remaining field = 5760 m².

As we know that

→ Volume of tank = 24 * 10 * 6

→ Volume of tank = 240 * 6

→ Volume of tank = 1400 m³.

Now,

Increase the level of field = Volume of tank ÷ Area of the remaining field.

→ Increase the level of field = 1400 ÷ 5760

→ Increase the level of field = 140 ÷ 576

→ Increase the level of field = 0.25 m.

Hence, the rise in the level of the field is 0.25 m.

Answer 2

$\huge{\boxed{\rm{\red{Question}}}}$

A field is 120m long & 50m broad. A tank 24m long, 10m broad & 6m deep is dug anywhere in the field and the earth taken out of the tank is evenly spread over the remaining part of the field. Find the rise in the level of the field.

${\bigstar}\large{\boxed{\sf{\pink{Given \: that}}}}$

• A field is 20 m long and 50 m broad. A tank 20 m long , 10 m broad and 6 m is dug anywhere in the field and the earth taken out of the tank is evenly spread over the remaining part of the field.

${\bigstar}\large{\boxed{\sf{\pink{To \: find}}}}$

• The rise in the level of the field.

${\bigstar}\large{\boxed{\sf{\pink{Solution}}}}$

• Let us take rise in level of the field =h cm
• Vol. of the earth spread = vol. of the tank
• Area of the remaining field times rise in level = vol. of the tank
• (Area of field-area of tank)*rise in level of field= vol. of the tank
• (120 × 50 − 24 × 10) × h = 24 × 10 × 6
• (6000− 240) × h = 1440
• (5760) × h = 1440
• 0.25m = 25cm
• Rise in level of the field= 25cm

$\large\orange{\texttt{Answer 0.25 m = 25 cm}}$

@Itzbeautyqueen23

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