Question

a field is 15 m long and 12 m broad at one corner of this field rectangular well of dimension 18 m x 2.5 m x 2 m is dug and the dug out soil is spread eventually over the rest of the field find the rise in the level of the rest of the field

Answer 1

Given Length of field = 15m.

Given breadth of field = 12m.

We know that Area of rectangle = length * breadth

                                                      = 15 * 12

                                                      = 180m^2.



Given that length of pit = 18m.

Given that breadth of pit = 2.5m.

Given that height of pit = 2m.

We know that volume = l * b * h

                                      = 18 * 2.5 * 2

                                      = 90m^3.


Area of the base of pit = 18 * 2.5

                                      = 45


Area of the remaining field = 180 - 45

                                              = 135m^2.


Let h be the height of the rise in the level of the field.

h = 90/135

   = 0.666 m

   = 66.66cm.


Hope this helps!

Answer 2

Answer
.................



Length of field = 15m.

breadth of field = 12m.


L = 15 cm

B = 12 cm

Area of rectangle = length * breadth

                                                     therefore

= 15 * 12

                  =
$= 180 \: m \: {}^{2}$



length of pit = 18m.

breadth of pit = 2.5m.

height of pit = 2m.




volume = l * b * h



   l = length
b = breath
h = height                                   = 18 * 2.5 * 2

                                      = 90m ^3


Area of the base of pit = 18 * 2.5

                                      = 45


Area of the remaining field = 180 - 45

                                              = 135m^2.


Let q be the height of the rise in the level of the field.

q = 90
_____. =. 0.666 m
135

 .    = 66.66cm.