Math, asked by babaimandal62, 11 months ago

A field is 150 m long and 80 m broad. A tank 40 m long, 20 m broad and
10 m deep is dug in the field and the earth taken out of it, is spread evenly
over the field. How much is the level of field raised ?

Answers

Answered by Lokeshydv2604
0

Answer:

1.4m

Step-by-step explanation:

Answered by mujeebkhan67
4

Answer:

Step-by-step explanation:

Given:

Length of field: 150 m

Broad of field: 80 m

Length of tank dug: 40 m

Broad of tank dug: 20 m

Depth of tank dug: 10 m

Area of field = Length of field * Broad of field = 150 m * 80 m = 12000 m^2

Volume of tank dug = Length of tank dug * Broad of tank dug * Depth of tank dug = 40 m * 20 m * 10 m = 8000 m^3

that means 8000 m^3 of sand dispersed over remaining field which is left over after dug of tank.

Level of field raised  = Volume of tank dug / Area of remaining field after tank dug

= 8000 m^3/ (Area of actual filed - Area of tank dug) m^2

= 8000 / (150 * 80 - 40 *20) m

= 8000 / 11200 m

= 0.714 m

= 71.4 cm

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