Question

A field is 16 1/2 m long and 12 2/5 m wide. Find the perimeter of the field.​

Answer 1

Step-by-step explanation:

Perimeter= 2(l+b)

l=16 1/2=16.5m

b=12 2/5=12.4m

perimeter=2(16.5+12.4)

=2×28.9

=57.8m

Answer 2

Step by step explanation:

$length \: of \: field \: = 16 \frac{1}{2} m \\ breadth \: of \: field \: = 12 \frac{2}{5}m \\ perimeter \: of \: field \: = 2(l + b) \\ = 2x( \frac{33}{2} + \frac{62}{5} ) \\ = 2x( \frac{33 + 5}{2x5} + \frac{62x2}{5x2} ) \\ (l.c.m \: of \: 2 \: and \: 5 = 10 \\ = 2x( \frac{165 + 134}{10} ) \\ = 2x \frac{289}{10} = \frac{289}{5} m = 57 \frac{4}{5} m$