a field is 225m long and 175 m wide it has two roads in it's center of uniform width of 5 m, one parallel to its breadth .find the cost of levelling the roads at RS 3 per square meter
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area of the road parallel to length=225×5 m^2
=1125 m^2 area ofroad parallel to width =175×5m^2=875m^2. so area of the path=(1125+875-5×5)m^2=1975m^2
so cost for levelling the road=rs.1975×3=rs.5925(ans)
=1125 m^2 area ofroad parallel to width =175×5m^2=875m^2. so area of the path=(1125+875-5×5)m^2=1975m^2
so cost for levelling the road=rs.1975×3=rs.5925(ans)
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Answer:
Rs.5925
Step-by-step explanation:
Analyse the problem.
We see that the total road to be levelled= horizontal road + vertical road - the common portion to both.
Area of horizontal road= 225m×5m=1125m^2
Area of vertical road=175m×5m=875m^2
Area of common portion: 5m×5m=25m^2
Thus total area:(1125+875−25)m^2
=1975m^2
Rate: Rs.3 per m^2
So, total cost=1975m^2 ×Rs.3
=Rs.5925m^2
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