Question

a field is 30 M long and 15m wide.Two path run parallel to the side of the rectangle through the centre of the field. The width of the longer path is 1.4 and that of the shorter path is 2 metre find the area of the path and the cost of the cementing the path rupees 70 per metre square​

Answer 1

Dimensions of a Field :

Length = 30 m,

Breadth = 15 m;

Dimensions of the path ABCD:

AB = 30 m, BC = 1.4 m !

Dimensions of the path EFGH:

EH = 15 m , EF = 2 m ,

Dimensions of KLMN:

KL = 2 m , ML = 1.4 cm ;

Now,

Area of the path

= Area of ABCD + Area of EFGH - Area of KLMN

= (AB × BC) + ( EH × EF ) - ( KL × ML )

= ( 30 × 1.4 ) + ( 15 × 2 ) - ( 2 × 1.4 )

= 42 + 30 - 2.8

= 72 - 2.8

= 69.2 square metres .

Given Cost of cementing 1 m² = Rs 70

Cost of cementing the Path = 70 × 69.2

= Rs 4844

Therefore.,

$\red { Cost \:of \: cementing \:the \:path} \green { = Rs \:4844}$

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