Question

a field is 30 metre long and 18 metre broad .A pit 6 m long,4 m wide and 3 metre deep is dug out from the middle of the field and the earth removed is evenly spread over the remaining area of the field find the rise in the level of the remaining part of the field in centimetres correct to 2 decimal places

Answer 1

The rise in the level of the remaining part of the field in centimeters correct to 2 decimal places is 13.95 centimeters.

Given that,

A field measures 30 meters long by 18 meters wide.

We have to calculate the rise in the level of the remaining portion of the field in centimeters with a precision of two decimal places after excavating a pit that is six meters long, four meters wide, and three meters deep in the middle of the field.

We know that,

Volume of the pit = 6×4×3 = 72

So,

Volume of earth taken out is equal to volume of earth spread in the remaining field

72 = [(30×18)-(6×4)]×h

72 = [540 - 24]×h

72 = 516 ×h

h = $\frac{72 \times 10^{6} }{516 \times 10^{4} }$

h = $\frac{7200}{516}$

h = 13.95 centimeters.

Therefore, the rise in the level of the remaining part of the field in centimeters correct to 2 decimal places is 13.95 centimeters.

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