Question

a field is 70 M long and 40m broad. In one corner of the field a pit which is 10 M long 8.5 M deep has been dug out. The earth taken out of it is evenly spread over the remaining part of the field. Find the rise in the level of the field

Answer 1

2nd part of your question seems to be incomplete, so I am solving the first part.

Area of the rectangular field = 70*40
= 2800 sq m
Volume of the earth taken out = L*B*H
= 10*8*5
= 400 cu m
Area of the pit = 10*8 
= 80 sq m
Area of the remaining filed = Area of the rectangular field - Area of the pit  
= 2800 - 80
Area of the remaining field = 2720 sq m
The earth taken out is evenly spread over the field of area 2720 sq m.

Let 'H' be the height of the rise in the level of the field.
∴ 2720 × H = 10*8*5
H = 400/2720
H = 5/34 m

Height in cm
H = (5*100)/34
H = 14.7 cm
So, the rise in the level of field is 14.7 cm
Answer.