A field is 80 m long and 50 m broad . in one corner of the field ,a pit which is 10 m long , 7.5 m broad and 8 m deep has been dug out . The earth taken out of it is evenly spread over the remaining part of the field . Find the rise in the level of the field . the ans is= 2400
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Solution:-
Length of field = 80 m
Breadth of field = 50 m
Length of pit = 10 m
Breadth of pit = 7.5 m
Height of pit = 8 m
Volume of earth taken out = volume of pit
= L*B*H
= 10*7.5*8
= 600 cu m
Area of rectangular field = 80*50
= 4000 sq m
Area of the base of pit = 10*7.5
= 75 sq m
Area of remaining portion of rectangular field = Area of rectangular field - Area of the base of pit
= 4000 - 75
= 3925 sq m
Now rise in the level of remaining part of the field = 600/3925
= 0.1528 m or 15.28 cm
So, rise in the remaining part of the field = 15.28 cm
Answer.
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