Question

A field is 90 m long and 40 m broad. In
one corner of the field, a pit (10 m long,
6 m broad and 8 m deep) is dug out. The
earth taken out is spread evenly over
the remaining part of the field. Find the
increase in the height of the field. ​

Answer 1

Answer:

13.333 cm

Step-by-step explanation:

Area of the rectangular field = 90*40

= 3600 sq m

Volume of the earth taken out = L*B*H

= 10*6*8

= 480 m³

Area of the pit = 10*6

= 60 sq m

Area of the remaining field = Area of the rectangular field - Area of the pit  

= 3600 m² - 60 m²

Area of the remaining field = 3540 sq m

The earth taken out is evenly spread over the field of area 3600 sq m.

Let 'H' be the height of the rise in the level of the field.

∴ 3600 × H = 10*6*8

H = 480/3600

H = 2/15 m

Height in cm

H = (2*100)/15

H = 13.333 cm

So, the rise in the level of field is 13.333 cm

Answer.

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Answer 2

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