Question

a field is in a shape of a trapezium whose parallel sides are of length 20 m and 10m .Non parallel sides are 13m each .Find area of field?

Answer 1

Given,

Parallel sides are 20 m and 10 m of trapezium ABCD respectively.

In order to find Area.

Construction :- Draw DM || CB.

Now, In figure there are two figures i.e. Isosceles triangle and a ||gm.

Now, In case of ||gm.

=> Ar(||gm MBCD) = Base x Height

=> Ar (||gm) = (10 x 13) m^2

=> Ar(||gm) = 130 m^2.

Again, In case of Triangle.

=> S = a+b+c/2 = 13+13+10/2 = 36/2 m = 18 m

$= > area \: = \sqrt{s(s - a)(s - b)(s - c)}$
$= > area \: = \sqrt{18(18 - 13)(18 - 13)(18 - 10)}$
$= > area \: = \sqrt{2 \times 3 \times 3 \times 5 \times 5 \times 2 \times 2}$
$= > area \: = (2 \times 2 \times 3 \times 5) \: {m}^{2}$
$= > area \: = 60 \: {m}^{2}$

Now,

Area of Trapezium = Ar(||gm)+ Area of Triangle

=> Area = (130 + 60) m^2 = 190 m^2

Answer 2

Step-by-step explanation:

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