Question

A field is in circular shape whose circumference is220m. Outside of the field, a road around it is constructed. If circumference of the road is 308m, find the width of road

Answer 1

Circumference of inner side = 220m

⇒2πr=220⇒r=

44

220×7

=35m

Now, width of track =7m

∴ Outer radius =35+7=42m

Therefore outer circumference =2πR=2×

7

22

×42=264m

∴ Cost of fencing = Rs. (264×2) = Rs. 528

please brainlest mark

Answer 2

Answer:

The width of the road is 14 m

Step-by-step explanation:

Circumference of inner circle = 220 m

Circumference of circle =2 \pi r2πr

2 \pi r = 2202πr=220

2 \times \frac{22}{7} \times r = 2202×

7

22

×r=220

r = \frac{220 \times 7}{22 \times 2}r=

22×2

220×7

r = 35r=35

So, Inner radius is 35 m

Circumference of outer circle = 308 m

2 \pi r = 308

2 \times \frac{22}{7} \times r =308

r = \frac{308 \times 7}{22 \times 2}

r=49 m

Width of road = Outer radius - Inner radius

Width of road = 49 m - 35 m

Width of road = 14 m

Hence the width of the road is 14 m

pls mark brainliest