A field is in shape of a trapezium whose parallel sides are 25m and 10m
The non-parallel sides are 14m and 13m. Find area of the field.
Answers
Answer:
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CD
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogram
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13m
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10m
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15m
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBEC
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formula
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²=84m²
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²=84m²Area of Δ BEC =½x CE x BF
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²=84m²Area of Δ BEC =½x CE x BF=84=12x15xBF
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²=84m²Area of Δ BEC =½x CE x BF=84=12x15xBFBF=16815=11.2m
Answer:Draw a line BE parallel to AD and draw a perpendicular BF on CDit can be observe that ABED is a parallelogramBE=AD=13mED=AB=10mEC=25-ED=15mfor ΔBECsemi perimeter S=13+14+15/2m42/2=21By heron formulaArea of Δ √s(s-a) (s-b) (s-c)Area of ΔABEC= √21 (21-13)(21-14)(21-15)m²[√21(8)(7)(6)]m²=84m²Area of Δ BEC =½x CE x BF=84=12x15xBFBF=16815=11.2mArea of the field = 84+112=196m2
Step-by-step explanation:
