Question

A field is in the form of a rhombus. The diagonals
of the field are 25 m and 40 m. Then the cost of
leveling it at the rate of 3 per m^2 is
Select one:
A. 1200
B.1500
c. 1600
D. 1300
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Answer 1

Given :-

• Diagonal (D1) = 25m
• Diagonal (D2) = 40m
• Rate of levelling the field is Rs.3 per m²

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To find :-

• Total cost of levelling the field.

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Solution :-

• We have length of both the diagonals of the field (rhombus).

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★ Area = ½ × D1 × D2

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→ Area = ½ × 25 × 40

→ Area = 25 × 20

→ Area = 500 m²

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Area of the field is 500 m².

As given in the question that rate of levelling the field is Rs.3 per m².

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Then, total cost of levelling is given by

★Total cost = Area(field) × Rate of levelling

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→ Total cost = 500 × 3

→ Total cost = Rs.1500

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Hence,

• The total cost of levelling the field is Rs.1500. Therefore option B is correct.

Answer 2

Given :-

→ First Diagonal of Rhombus = 25 m

→ Second Diagonal of Rhombus = 40 m

→  Cost of leveling per m² = Rs. 3

To Find :-

→ Cost of levelling this Rhombus shaped field

Solution :-

→ As we're given to find the cost of levelling , we need to find the area of the field first .

$\underline{\bf{\dag} \:\mathfrak{As\;we\;know\: that\: :}}$

$\star\: \boxed{\sf{\blue{Area\;of\;Rhombus\;=\frac{1}{2} \times 1^{st} Diagonal \times 2^{nd}Diagonal }}}$

→ Let's find out by putting values in this formula !

$\sf \implies \dfrac{1}{2} \times 25\;m \times 40\;m$

$\sf \implies 25\;m \times 20\;m$

$\sf \implies 500\;m^{2}$

→ ATQ , Now we need to find the cost by using the unitary method

$\sf \implies 1\;m^{2} = Rs. 3$

$\sf \implies 500\;m^{2} = 500 \times 3$

$\sf \implies Rs.15,00$

∴ Cost of levelling this field will be Rs. 15,00

More to Know :-

➝ Area of square = Side × Side

➝ Area of Rectangle = Length × Breadth

➝ Area of Triangle = 1/2 × Base × Height

➝ Area of Rhombus = 1/2 × Product of Diagonals

➝ Area of Circle = πr²

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