A field is in the form of a rhombus whose each side 81 m and the altitude is 25 m. Find the side of a square field whose area is equal to that of the rhombus . Find the different in the perimeter
Answers
GIVEN :-
side of the rhombus field = 81m
altitude of the rhombus field = 25m
we know that rhombus is also a parallelogram whose side is the base
formula to find the area of a parallelogram = base × height
so we can write,
area of the rhombus field = base × height
= 81 × 25
= 2025m²
ATQ, the area of the square field = area of the rhombus field
therefore area of the square field = 2025m²
we know the formula to find the area of a square, that is side × side or side²
➡ side² = 2025m²
➡ side = √2025
➡ side = 45m
now, both the formulas to find the perimeter of a square and a rhombus is same since they have 4 equal sides.
- perimeter of the rhombus field = 4 × 81 = 324m
- perimeter of the square field = 4 × 45 = 180m
hence, difference between their perimeters = 324 - 180
= 144m FINAL ANSWER
Answer :
Difference between their perimeters = 144m
Step-by-step explanation :
Given that :
Side of the rhombus field = 81m.
Altitude of the rhombus field = 25m.
Remember :
We know that :
Put the values :
= 81 × 25
= 2025m²
As given The area of the square field = Area of the rhombus field.
Hence,
We also know that :
Put Values :
Now to find :
Perimeter of a square and a rhombus.
So,
Perimeter of the rhombus field:
=> 4 × 81
=> 324m
Perimeter of the square field:
=> 4 × 45
=> 180m
Differnce :
324 - 180 = 144.
Hence,
Difference between their perimeters = 144m.