Question

a field is in the form of a rhombus whose each side is 64cm and altitude is 16cm. Find the side of a square field whose area is equal to that of a rhombus.find the difference in their perimeter​

Answer 1

Answer:

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Step-by-step explanation:

Side of rhombus is 81m and its altitude is 25m.

Area of rhombus = side * altitude = 81*25 sqm.

Area of square = 81*25 sqm.

So side of square = sqrt(81*25)= 9*5 = 45m

Perimeter of a rhombus = 4 × 81 = 324m

perimeter of a square = 4 × 45 = 180m

Their difference = 324 - 180 = 144m

I hope it is clear for you.

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[Thank you].

Answer 2

Answer:

128 cm

Step-by-step explanation:

Area of rhombus = base * altitude

= 64 * 16

= 1024 cm²

Perimeter of rhombus = 4 * 64 = 256 cm

Area of square = length * length

                         = 1024 (Area of square = rhombus)

Area of square = 1024 m².

Length of each side of square = √1024 = 32 cm.

Perimeter of square = 4 * 32 = 128 cm

Difference between their perimeters :

= 256 - 128

= 128 cm

Therefore,

Difference in their perimeter = 128 cm.

Hope it helps!