Question

A field is in the form of a rhombus whose each side is 81 M and altitude is 25 m.find the area of a square field whose area is equal to that of the Rhombus find the difference in their perimeter

Answer 1

Area of rhombus=Base×Altitude
=81×25
=2025
Now,area of square=area of rhombus (given).
therefore,(a)²=2025
a=√2025
a=45

NOW, Perimeter of rhombus=4×81=324
and, Perimeter of square=4×45=180
so, the difference in their perimeters is
perimeter of rhombus- perimeter of square
324-180=144
HOPE IT IS HELPFUL!