A field is in the form of a rhombus whose side is 81 m and height is 64 m. Find the side of a square field whose area is equal to that of the rhombus shaped field. Also, find the difference between their perimeters.
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Answer:
36m
Step-by-step explanation:
area of rohmbus=base×altitude
=81×64
=5184sq.
perimeter of rohmbus=4×81
=324m
area of square=5184 sq.m.
length of a side of a square=√5184
=72m
perimeter of square=4×72=288
difference in their perimeter=324-288
=36m
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