a field is in the form of a right angle with hypotenuse 50m and one side 30 m find the area of a field
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Hypotenuse = 50 m
One side = 30 m
By Using Pythagoras
(HY)² = (B)² + ( AL)²
(50)²= (B)²+ (30)²
2500= B² + 900
2500-900 = B²
1600 = B²
√1600 = B
40 = B
B = 40 m
Area = 1/2 × b× h
= 1/2×40×30
= 20×30
=600 m²
One side = 30 m
By Using Pythagoras
(HY)² = (B)² + ( AL)²
(50)²= (B)²+ (30)²
2500= B² + 900
2500-900 = B²
1600 = B²
√1600 = B
40 = B
B = 40 m
Area = 1/2 × b× h
= 1/2×40×30
= 20×30
=600 m²
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